The value of `K_(c )` for the reaction `3O_(2)(g) hArr 2O_(3)(g)` is `2.0xx10^(-50)` at `25^(@)C`. If the equilibrium concentration of `O_(2)` in air at `25^(@)C` is `1.6xx10^(-2)`, what is the concentration of `O_(3)`?

Explanation

`K_c=([O_3]^2)/([O_2]^3)`
`2.0xx10^(-50)=([O_3]^2)/(1.6xx10^(-2))^3)`
or `[O_3]^2 =2.0xx10^(-50)xx(1.6xx10^(-2))^3 =8.192xx10^(-56)`
`[O_3]=2.86xx10^(-28)` M