Find out the value of `K_c` for each of the following equilibria from the value of `K_p` :
(i)`2NOCl(g) hArr 2NO(g) + Cl_2(g) , K_p=1.8xx10^(-2)` at 500 K
(ii)`CaCO_3(s) hArr CaO(s) +CO_2(g) , K_p` = 167 at 1073 K

Explanation

`2NOCl hArr 2NO(g) + Cl_2(g)`
`K_p = 1.8xx10^(-2)` at 500 K
`Deltan` =3-2=1
`K_c=K_p(RT)^(-Deltan_g)`
`=1.8xx10^(-2) (0.0831xx500)^(-1) =4.33xx10^(-4)`
(ii)`Deltan`=1-0=1
`K_c=K_p(RT)^(-Deltan_g)`
`=167xx(0.0831xx1073)^(-1)` =1.87