Home
Class 11
CHEMISTRY
Calculate the hydrolysis constant for 0....

Calculate the hydrolysis constant for 0.1 M sodium acetate solution. `(K_a=1.8xx10^(-5))`

Text Solution

AI Generated Solution

To calculate the hydrolysis constant (K_h) for a 0.1 M sodium acetate solution, we can follow these steps: ### Step 1: Understand the components Sodium acetate (CH₃COONa) is a salt formed from a weak acid (acetic acid, CH₃COOH) and a strong base (sodium hydroxide, NaOH). In solution, sodium acetate will hydrolyze to produce acetate ions (CH₃COO⁻) and sodium ions (Na⁺). ### Step 2: Write the hydrolysis reaction The hydrolysis of the acetate ion can be represented as follows: \[ \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^- \] ...
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Revision Exercise ( short )|44 Videos
  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Revision Exercise ( Long )|13 Videos
  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Revision Exercise (Assertion Reason )|15 Videos
  • ENVIRONMENTAL POLLUTION

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|15 Videos
  • HALOALKANES AND HALOARENES

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|12 Videos

Similar Questions

Explore conceptually related problems

Calculate the degree of hydrolysis and pH of a 0.1 M sodium acetate solution. Hydrolysis constant for sodium acetate is 5.6 xx 10^(-10).

Calculate the percent hydrolysis in a 0.0100 M solution of KCN. (K_a= 6.2 xx 10^(-10))

Calculate degree of hydrolysis and pH of 0.25 NaCN solution at 25^@C . K_a=4.8xx10^(-10)

Calculate the degree of hydrolysis of 0.1 M solution of sodium acetate at 298 K : K_(a) = 1.8 xx 10^(-5) .

Calculate the degree of hydrolysis of 0.1 M solution of acetate at 298 k. Given : K_a=1.8xx10^(-5)

Calculate the percent hydrolysis in a 0.06 M solution of KCN. [K_a(HCN) = 6 xx 10^(-10)]

Calculate the degree of hydrolysis and hydrolysis constant of 0.01 M solution of NH_(4)CI . Given K_(w) =1 xx 10^(-14) , K_(b) =1.75 xx 10^(-5)

pK_(a) value for acetic acid at an experimental temperature is 5. The percentage hydrolysis of 0.1 M sodium acetate solution will be

MODERN PUBLICATION-EQUILIBRIUM-Revision Exercise (Very short )
  1. What is the effect of having the pressure by doubling the volume on th...

    Text Solution

    |

  2. Explain why pure liquids and solids can ignored while writing the equi...

    Text Solution

    |

  3. The value of K(c) for the following equilibrium is CaCO(3(s))hArrCaO...

    Text Solution

    |

  4. What are amphoteric substances ? Give one example.

    Text Solution

    |

  5. What are conjugate acid base pairs. Give two examples.

    Text Solution

    |

  6. What is the pH of 0.1 M HCl?

    Text Solution

    |

  7. Calculate the concentration of SO4^(2-) ions necessary to cause the pr...

    Text Solution

    |

  8. Why is ammonia termed as Lewis base?

    Text Solution

    |

  9. What is the concentration of H3O^+ and OH^- ions in water at 298 K ?

    Text Solution

    |

  10. Calculate the pH of 0.001 M HCl solution.

    Text Solution

    |

  11. Give the conjugate acids of OH^(-), HSO4^(-) and NH3.

    Text Solution

    |

  12. State the conjugate acid-base pairs in the following : CO3^(2-) + H...

    Text Solution

    |

  13. Define solubility product.

    Text Solution

    |

  14. What do you understand by common ion effect?

    Text Solution

    |

  15. For the aqueous solution of a salt of a weak acid and a weak base,

    Text Solution

    |

  16. The aqueous solution of copper(II) sulphate is slowly hydrolysis formi...

    Text Solution

    |

  17. Which salt undergoes hydrolysis?

    Text Solution

    |

  18. Define degree of hydrolysis.

    Text Solution

    |

  19. Will the pH of an aqueous solution of NH4Cl greater, equal or less tha...

    Text Solution

    |

  20. Calculate the hydrolysis constant for 0.1 M sodium acetate solution. (...

    Text Solution

    |