For the reversible reaction
`N_(2)(g)+3H_(2)(g)hAr2NH_(3)(g)`
at `500^(@)C` the value of `K_(p)` is `1.44xx10^(-5)` when partial pressure is measured in atmosphere. The corresponding value of `K_(e)` with concentration in mol/L is

Options

A. `1.44xx10^(-5)//(0.082xx500)^(-2)`
B. `1.44xx10^(-5)//(8.314xx733)^(-2)`
C. `1.44xx10^(-5)//(0.082xx773)^2`
D. `1.44xx10^(-5)//(0.082xx773)^(-2)`

Answer

D

Explanation

`Deltan_g`=2-(1+3)=-2
`K_p=1.44xx10^(-5)`
`K_p=K_c(RT)^(Deltan_g)`
or `K_c=K_p/(RT)^(Deltan_g) =(1.44xx10^(-5))/(0.082xx77)^(-2)`
`=1.44xx10^(-5)//(0.082xx773)^(-2)`