The `[OH^-]` of an aqueous solution is `1xx10^(-5)` . The pH of the solution is :

Options

A. 5
B. 9
C. 4.5
D. 11

Explanation

To find the pH of the solution given the hydroxide ion concentration \([OH^-] = 1 \times 10^{-5}\), we can follow these steps:

### Step 1: Calculate the pOH
The pOH of a solution can be calculated using the formula:
\[ \text{pOH} = -\log[OH^-] \]
Substituting the given concentration:
\[ \text{pOH} = -\log(1 \times 10^{-5}) \]

### Step 2: Simplify the logarithm
Using the properties of logarithms:
\[ \text{pOH} = -(-5) = 5 \]

### Step 3: Calculate the pH
We can relate pH and pOH using the formula:
\[ \text{pH} + \text{pOH} = 14 \]
Now substituting the value of pOH:
\[ \text{pH} + 5 = 14 \]

### Step 4: Solve for pH
Rearranging the equation gives:
\[ \text{pH} = 14 - 5 = 9 \]

### Final Answer
The pH of the solution is \(9\).

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