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A solution is 10^(-3) M each in Mn^(2+),...

A solution is `10^(-3)` M each in `Mn^(2+),Fe^(2+),Zn^(2+)` and `Hg^(2+)` is treated with `10^(-16)` M sulphide ion, If `K_(sp)` values of MnS, FeS, ZnS and HgS are `10^(-15),10^(-23),10^(-20)` and `10^(-54)` respectively, which one will precipitate first?

A

FeS

B

HgS

C

HgS

D

ZnS

Text Solution

Verified by Experts

The correct Answer is:
C
The salt having lowest `K_(sp)` will precipitate out first i.e., HgS
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