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The threshold wavelength for the ejectio...

The threshold wavelength for the ejection of electron for metal X is 330 nm. The work function for photoelectric emission from metal X is `(h=6.6xx10^(-34)Js)`

A

`1.2xx10^(-18)J`

B

`1.2xx10^(20)J`

C

`6xx10^(-19)J`

D

`6xx10^(-12)J`

Text Solution

Verified by Experts

The correct Answer is:
C
Work function
`hv_(0)=(hc)/(lamda_(0))=(6.6xx10^(-34) xx3.0xx10^(8))/(330xx10^(-9))` `=6.0xx10^(-19)J`
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