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The wavelength of the first line of Balm...

The wavelength of the first line of Balmer series of H-atom of `6561Å`. The wavelength of the second line of the series is

A

`13122Å`

B

`3280Å`

C

`4860Å`

D

`2180Å`

Text Solution

Verified by Experts

The correct Answer is:
C
`1/(lamda_(1))=R(1/(2^(2))-1/(3^(2)))`
or `1/6561=R(1/4-1/9)=5/36R`
`1/(lamda_(2))=R(1/(2^(2))-1/(4^(2)))`
or `1/(lamda_(2))=R(1/4-1/16)=3/16 R`
`:.1/6561xx(lamda_(2))/1=5/36xx16/3`
or `lamda_(2)=(5xx16xx6561)/(36xx3)=4860Å`
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