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The energy of an electron in te first B...

The energy of an electron in te first Bohr orbit of H atom is -13.6eV. The possible energy values(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (ar)

A

`-3.4eV`

B

`-4.2eV`

C

`-6.8eV`

D

`+6.8eV`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(2)=-13.6/(2^(2))=-3.4eV`
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