Home
Class 12
CHEMISTRY
At 200^(@)C, the velocity of hydrogen mo...

At `200^(@)C`, the velocity of hydrogen molecules is `2.4xx10^(5)` cm/sec. In this case the de-Broglie wavelength is about

A

`1Å`

B

`1000Å`

C

`100Å`

D

`10Å`

Text Solution

Verified by Experts

The correct Answer is:
A
Velocity of hydrogen `=2.4xx10^(5)`cm/sec
`=2.4xx10^(3)`m/sec
Mass of hydroge `=2/(60.2xx10^(23))`
`=3.32xx10^(-24)m-3.32xx10^(-27)kg`
`lamda=h/(mv)=(6.6xx10^(-34))/(3.32xx10^(-27)xx2.4xx10^(3))`
`=0.83xx10^(-10)m=1Å`
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL II)|90 Videos

  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL III)|10 Videos

  • STATES OF MATTER

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|12 Videos

  • SURFACE CHEMISTRY

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|15 Videos

Similar Questions

Explore conceptually related problems

If the velocity of the electron in Bohr's first orbit is 2.19xx 10^(6) ms^(-1) , calculate the de-Broglie wavelength associated with it.

(a) For what K.E. of a neutron, will the associated de Broglie wavelength be 1.40xx 10^(-10)m ? (b) Also find the de - Broglie wavelength of a neutron, in thermal equilibrium with matter, having an average kinetic energy of (3//2) kT at 300K

The velocities of a proton and alpha particle are in the ratio 4 : 1, the ratio of their de Broglie wavelength is

An electron is revolving around the nucleus with a constant speed of 2.2 xx 10^(8) m//s . Find the de-Broglie wavelength associated with it.

If the total energy of anelectron in a hydrogen like atom in excited state is -3.4eV ,then the de Broglie wavelength of the electron is

In the Bohr model of hydrogen atom. What is the de-Broglie wavelength lambda for the electron when it is in the (i) n = 1 level (ll) n = 4 level. In each case, compare the de-Broglie wave length to the circumference of the orbit. Data: n=1, n=4, lambda =?

A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813 xx 10^(-4) . Calculate the particle’s mass and identify the particle.