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The kinetic energy of the electron emitt...

The kinetic energy of the electron emitted when light of frequency `3.5xx10^(15)Hz` is made to strike on a metal surface havng threshold frequency `1.5xx10^(15)Hz` is
`(h=6.6xx10^(-34)Js)`

A

`1.32xx10^(-18J`

B

`3.3xx10^(-18)J`

C

`6.6xx10^(-19)J`

D

`1.98xx10^(-19)J`

Text Solution

Verified by Experts

The correct Answer is:
A
`KE=hv-hv_(0)=h(v-v_(0))`
`=6.6xx10^(-34)(3.5xx10^(15)-1.5xx10^(15))`
`=1.32xx10^(-18)J`
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