Energy of the electron in hydrogen atom is 1.5 timesas much ass the minimum energy required for its escape (13.6eV) from the atom. Wavelength of the emitted electron is

Options

A. `3.96Å`
B. `5.32Å`
C. `4.60Å`
D. `4.71Å`

Answer

D

Explanation

Electron in the ground state absorbs inerg and the difference in energy provides K.E. to the emitted electron.
`E_(1)=13.6eV`
`E_(2)=13.6xx1.5=20.4eV`
`DeltaeE=K.E. =20.4-13.6=6.8xx1.6xx10^(-19)J`
`lamda=h/(sqrt(2mKE))`
`=(6.61xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx6.8xx1.6xx10^(-19)))`
`=4.71xx10^(-10)m=4.71Å`