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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in 2s orbital

A

`+1/2h/(2pi)`

B

zero

C

`h/(2pi)`

D

`sqrt(2).h/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
Orbital angular momentum
`=sqrt(l(l+1))h/(2pi)=0" " ( :. l=0)`
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