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For an electron having s=1//2, the spin ...

For an electron having `s=1//2`, the spin anglar momentum is

A

`(sqrt(3)h)/(4pi)`

B

`sqrt(3)`

C

`sqrt(2)`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
A
Spin angular momentum`=sqrt(s(s+1))h/(2pi)`
for s=1/2
Spin angular momentum `=sqrt(1/2(1/2+1)). h/(2pi)`
`=sqrtS(1/2xx3/2). h/(2pi)=(sqrt(3).h)/(4pi)`
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