The highest excited state that an unexcited hydrogen atom can reach when they are bombarded with 12.75 eV of energy is :

Options

A. n=2
B. n=3
C. n=4
D. n=5

Answer

C

Explanation

`E_(1)=-13.6eV`
After absorption of 12.75 eV, energy of electron `=-13.6+12.75=-0.85`
`E_(n)=(E_(1))/(n^(2))impliesn^(2)=(E_(1))/(E_(n))=-(13.6)/(-0.85)=16`
`:.n=4`