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The velocity of an electron in Bohr's fi...

The velocity of an electron in Bohr's first orbital of la H-atom is `2.16xx10^(6)ms^(-1)`. Its velocity in the second orbit would be

A

`1.08xx10^(6)ms^(-1)`

B

`0.54xx10^(6)ms^(-1)`

C

`4.32xx10^(6)ms^(-1)`

D

`8.64xx10^(6)ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Velocity `prop 1/n`
`(v_(2))/(v_(1))=(n_(1))/(n_(2))`
`:.v_(2)=v_(1)xx(n_(1))/(n_(2))=2.16xx10^(2)xx1/2`
`=1.08xx10^(5)ms^(-1)`
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