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In hydrogen atom, energy of first excite...

In hydrogen atom, energy of first excited state is-3.4eV. The K.E. of the same orbit of H-atom is

A

`+3.4eV`

B

`+6.8eV`

C

`-13.6eV`

D

`+13.6eV`

Text Solution

Verified by Experts

The correct Answer is:
A
Energy in excited state means K.E.
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