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Ionisation energy of He^(+) is 19.6xx10^...

Ionisation energy of `He^(+)` is `19.6xx10^(-18)J"atom"^(-1)`. The energy of first stationary state (n=1) of `Li^(2+)` is

A

`-2.2xx10^(-15)"atom"^(-1)`

B

`8.82xx10^(-178)J"atom"(-1)`

C

`4.41xx10^(-16)J"atom"^(-1)`

D

`-4.41xx10^(-17)J"atom"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
IE of`He^(+)`ion= IE of Hatom`xxZ^(2)` `19.6xx10^(-18)J"atom"^(-1)=4xx` I.E. of H atom
`:.`I.E of Hatom `=(19.6xx10^(-18))/4`
`=4.9xx10^(-18)J"atom"^(-1)`
I.E of `Li^(2-)` ion = I.E. of H atom `xx(3)^(2)`
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