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The frequency of light emitted for the t...

The frequency of light emitted for the transition n=4 to n=2 of `He^(+)` is equal to the transition in H atom corresponding to which of the following?

A

n=2 to n=1

B

n=3 to n=2

C

n=4 to n=3

D

n=3 to n=1

Text Solution

Verified by Experts

The correct Answer is:
A
`v(H)=v(HE^(+))`
`[RZ^(2)(1/(n_(1)^(2))-1/(n_(2)^(2)))]_(H)=RZ^(2)(1/(n_(1)^(2))-1/(n_(2)^(2)))_(He^(+))`
`1/(n_(1)^(2))-1/(n_(2)^(2))=4(1/4-1/16)`
`1/(n_(1)^(2))-1/(n_(2)^(2))=1/1-1/4`
`:.n_(1)=1` and `n_(2)=2`
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