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Energy of an electron is given byE=-2.17...

Energy of an electron is given by`E=-2.178xx10^(-18)J((Z^(2))/(n^(2)))`. Wavelength of light required to excite an electron in an hydrogen atom from level n=1 to n=2 will be:

A

`1.214xx10^(-7)m`

B

`2.816xx10^(-7)m`

C

`6.500xx10^(-7)m`

D

`8.500xx10^(-7)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(1)=-2.178xx10^(-18)xx(1^(2))/(1^(2))=-2.178xx10^(-18)J`
`E_(2)=-2.178xx10^(-18)xx(1^(2))/(2^(2))=-5.445xx10^(-19)J`
Energy required to excite electron from level n=1 to n=2
`DeltaE=-5.445xx10^(-19)-(-2.178xx10^(-18))`
`=16.335xx10^(-19)J`
`(hc)/(lamda)=16.335xx10^(-19)`
or `lamda=(6.63xx10^(-34)xx3.0xx10^(8))/(16.335xx10^(-19))`
`=1.217xx10^(-7)m`
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