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According to Charles' law, at constant p...

According to Charles' law, at constant pressure 100ml of a given mass of a gas with `10^(@)C` rise in temperature will become `( ( 1)/( 273) = 0.00366)`

A

1. 100.0366

B

2. 99.9634

C

3. 103.66

D

4. 100.366

Text Solution

Verified by Experts

The correct Answer is:
C
`V_(t) = V_(0) + V_(0) xx 10 xx 0.0036`
`= 100 + 100 xx 10 xx 0.0036`
`= 103.66`
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