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56g of N(2) ( molar mass = 28) are mixed...

56g of `N_(2)` ( molar mass = 28) are mixed with 44g of `CO_(2)` ( molar mass = 44) and the pressure of the resulting gaseous mixture is 3 atm. The partial pressure of `N_(2)` in the mixture is `:`

A

i. 1 atm

B

ii. 1.5 atm

C

iii. 2 atm

D

iv. 3 atm

Text Solution

Verified by Experts

The correct Answer is:
C
Moles of `N_(2) = ( 56)/( 28) =2 `
Moles of `CO_(2) = ( 44)/( 44) = 1 `
Mole fraction of
`N_(2) = ( 2)/( 2+1) = ( 2)/(3)`
Partial pressure of
`N_(2) = ( 2)/(3) xx 3 = 2 atm`
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