Home
Class 12
CHEMISTRY
According to Graham's law at a given tem...

According to Graham's law at a given temperature the ratio of the rates of diffusion `r_(A) //r_(B)` of gases A and B is given by

A

`( P_(A) //P_(B)) ( M_(A) //M_(B))^(1//2)`

B

`(M_(A) //M_(B) )(P_(A) //P_(B))^(1//2)`

C

`(P_(A) //P_(B)) ( M_(B) //M_(A))^(1//2)`

D

`(M_(A) //M_(B)) ( P _(B)//P_(A))^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL-II)|95 Videos

  • STATES OF MATTER

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL-III)|7 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTION|15 Videos

  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|11 Videos

Similar Questions

Explore conceptually related problems

When r,P and M represent rate of diffusion, pressure and molecular mass respectively, then the ratio of the rates of diffusion ( r_(A) //r_(B)) of two gases A and B , is given as :

The ratio of rates of diffusion of hydrogen chloride and ammonia gases is

The influence of temperature on the rate of reaction is given by :

The rate law for reaction between the substances A and B is given by : Rate = k [A]^(n) [B]^(m) on doubling the concentration of A and halving the cocentration of B the ratio of the new rate to the earlier rate of reaction will be :

Two separate bulbs contain ideal gases A and B respectively. The density of gas A is twice that of gas B and the molar mass of gas A is half that of gas. If the two gases are at the same temperature, the ratio of pressure of A to that of B is :

Two sample of gases A and B are at the same temperature. The molecules of A are travelling 4 times faster than molecules of B. The ratio M_(A) //M_(B) of their masses will be