Home
Class 12
CHEMISTRY
The total kinetic energy of 2 mol of an ...

The total kinetic energy of 2 mol of an ideal gas at `127^(@)C` is ( Use R = 8.3 `JK^(-1) ``mol^(-1)` )

A

9.96 kJ

B

19.92kJ

C

3.32kJ

D

39.84kJ

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL-II)|95 Videos
  • STATES OF MATTER

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL-III)|7 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTION|15 Videos
  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIONS|11 Videos

Similar Questions

Explore conceptually related problems

The maximum work obtained by an isothermal reversible expansion of 1 mol of an ideal gas at 27^(@)C from 2.24 to 22.4L is (R = 2 cal)

Two reactions of the same order have equal preexponential factors but their activation energies differ by 24.9 kJ mol^(-1) .The ratio of their rate constants at 27^@C (R = 8.3JK^(-1) mol^(-1) ) is :

The specific reaction rate of a reaction quadruples when temperature changes from 30°C to 50°C. Calculate the energy of activation of the reaction [Given : R = 8.314 "JK"^(-1) "mol"^(-1) ]

A plot of (1)/(T) Vsk for a reaction gives the slope - 1 xx 10^(4)K . The energy of activation for the reaction is (Given R = 8.314 JK^(-1) " mol"^(-1) )

(Delta U - Delta H) for the formation of carbon monoxide (CO) from its elements of 298 K is (R = 8.314 JK^(-1) mol^(-1))

(a) Derive an integrated rate equation for the rate constant of a first order reaction. (b) The specific reaction rate of a reaction quadruples when temperature changes from 30^(0) to 50^(0) .Calculate the energy of activation of the reaction. [Given : R = 8.314 JK^(-1)mol^(-1)] .