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The temperature of an ideal gas is incre...

The temperature of an ideal gas is increased from 140K to 560K. If at 140K, the root mean square velocity of the gas is x, at 560K it becomes

A

5x

B

4x

C

2x

D

`x//2`

Text Solution

Verified by Experts

The correct Answer is:
C
r.m.s. speed at 10 K = x
`:. x = sqrt(( 3R xx 560 )/( M ))`
at 560K,x. = `sqrt(( 3R xx 560)/( M))`
`( x.)/( x) = sqrt(( 560)/( 140)) = 2`
`x. = 2x`
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