The number of molecules of an ideal gas in a 4.1 L container at 760 torr and `27^(@)C` will be

Options

A. `6.02 xx 10^(23)`
B. `1.0 xx 10^(23)`
C. `1.204 xx 10^(24)`
D. `1.204 xx 10^(23)`

Answer

B

Explanation

Number of moles
`pV = nRT`
or ` n = ( pV)/( RT )`
`:. n = ( 1 ( atm ) xx 4.1 ( L))/( 0.082 xx 300)`
`:.` Number of molecules
`= ( 4.1 )/( 0.082 xx 300) xx 6.02 xx 10^(23)`
`= 1.0 xx 10^(23)`