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If 4g of O(2) diffuse through a very nar...

If 4g of `O_(2)` diffuse through a very narrow hole, how much `H_(2)` would have diffused under identical conditions ?

A

1g

B

`1//4g`

C

`16g`

D

64g

Text Solution

Verified by Experts

The correct Answer is:
C
`( 4g//t)/(x//t) = sqrt((2)/( 32))`
( x is the amount of `H_(2)` diffused and t is the time )
`( 4)/( x) = sqrt((1)/( 16)) = ( 1)/( 4)`
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