In the same time required for 5 litres of carbon monoxide to diffuse through a porous barrier, only 2 litres of an unknown gas will pass through . The molecular mass of unknown gas is `:`

Options

A. 70
B. 11.2
C. 175
D. 4.48

Answer

C

Explanation

Let the time required is t.
`( rate ( CO_(2)))/( "rate ( unknown gas )") = ( 5//t)/( 2 //t)`
`= sqrt(("M ( unknown gas)")/(44))`
`= ( 25)/( 4) = ( "M ( unknown gas)")/( 44)`
`:. ` M (unknown gas ) = `( 25 xx 44)/( 4) = 175`