When the pressure and absolute temperature of 5L nitrogen are doubled, the gas would have a volume of `:`

Options

A. 10L
B. 5L
C. 15L
D. 20L

Answer

B

Explanation

`p_(1) =p`, `p_(2) = 2p`,
`T_(1) = T, T_(2) = 2T`,
`V_(1) = 5L, V_(2) = ?`
`( \p_(1) V_(1))/( T_(1)) = ( p _(2) V_(2))/( T_(2))`
or `V_(2) = ( p_(1) V_(1) T_(2))/( T_(1) p _(2))`
`= ( p xx 5 xx 2T )/( T xx 2p ) = 5L`