4.0g of argon ( at. Mass = 40) in a bulb at a temperature of T K has a pressure P atm. When the bulb was placed in a hotter bath at a temperature `50^(@)C` more than the first one, 0.8g of gas had to be removed to get the original temperature T which is equal to

Options

A. 510K
B. 200K
C. 100K
D. 73 K

Answer

B

Explanation

Moles of argon `= ( 4)/( 40) =0.1`
Now, `p V = nRT`
or `pV = 0.1 RT `
In hot bath, n `= ( 4.0 - 0.8)/( 40) = 0.08`
`:. pV = 0.08 R ( T + 50)`
`:. 0.1 RT = 0.08 R ( T + 50)`
or `T = 200K`