The root mean square velocity of a gas molecule at 100K and 0.5 atm pressure is 106.4 `ms^(-1)`. If the temperature is raised to 400k and the pressure is raised to 2 atm, the root mean square velocity becomes

Options

A. `106.4 ms^(-1)`
B. `425.6 ms^(-1)`
C. `212.8 ms^(-1)`
D. `851.2 ms^(-1)`

Answer

C

Explanation

`C_(p ) -C_(v) =R` ( for monoatomic gas )
`:. C_(p ) = R + C_(v) = R + ( 3)/( 2) R = ( 5)/( 2) R `