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If the root mean square speed of helium ...

If the root mean square speed of helium is `4.75 m s^(-1)` at `25^(@)C`, then its speed will become 9.50 m`s^(-1)` at

A

`100^(@)C`

B

`323^(@)C`

C

`919^(@)C`

D

`1192^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
r.m.s. speed `prop sqrt( T )`
`( 4.75 )/( 9.50) = sqrt(( 298)/( T))`
or `( 4.75^(2))/(9.50) = ( 298)/( T )`
or `T =1192 K`
or `T = 1192 - 273 = 919^(@)C`
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