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A 10L cylinder of nitrogen at 4.0 atm pr...

A 10L cylinder of nitrogen at 4.0 atm pressure and `27^(@ C` develped a leakage. When the leakage was repaired 2.36 atm of nitrogen remained in the cylinder still at `27^(@0C`. How many grams of nitrogen escaped ?

A

18.7 g

B

0.67g

C

52.6g

D

10.0g

Text Solution

Verified by Experts

The correct Answer is:
A
Moles of `N_(2)` escaped
`= ( 4 xx 10)/( 0.082 xx 300) - ( 2.36 xx 10)/( 0.082 xx 300) = 0.667`
Mass of `N_(2) = 0.667 xx 28 = 18.7 g `
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