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The volume of NH(3) obtained by the comb...

The volume of `NH_(3)` obtained by the combination of 10mL of `N_(2)` and 30 mL of `H_(2)` is

A

20 mL

B

40 mL

C

30 Ml

D

10 mL

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(2)( g) + 3H_(2)( g) rarr 2NH_(3) ( g)`
`1 vol" " 3 vol rarr 2 vol`
`10 mL " " 30 mL rarr 20 mL`
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