At same temperature and pressure, the rate of diffusion of hydrogen gas is `3 sqrt( 3)` times that of a hydrocarbon having molecular formula, `C_(n) H_(2n-2)`.The value of n is

Options

A. 3
B. 2
C. 6
D. 4

Answer

D

Explanation

`( r ( H_(2)))/( "r ( hydrocarbon)") = sqrt(("M(hydrocarbon)")/(M(H_(2))))`
`3 sqrt( 3) = sqrt(("M(hydrocarbon)")/(2))`
M ( hydrocarbon) = `(3sqrt( 3))^(2) xx 2 = 54 `
For `C_(n)H_(2n-2) .12n+(2n-2) = 54`
or n = 4