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If r.m.s. speed of gaseous molecules is ...

If r.m.s. speed of gaseous molecules is `x cm s^(-1)` at a pressur eof p atm, their r.m.s. at a pressure of 2 atm and constant temperature will be

A

x

B

2x

C

4x

D

`x//4`

Text Solution

Verified by Experts

The correct Answer is:
A
`u = sqrt((3RT)/( M)) = sqrt((pV)/( M))`
As temperature is constant, pV is constant. Therefore, r.m.s. speed is constant even if pressure is doubled.
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