The pressure and temperature of `4 dm^(3)` of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be

Options

A. `2 dm^(3)`
B. `3dm^(3)`
C. `4dm^(3)`
D. `8 dm^(3)`

Answer

C

Explanation

`(p_(1)V_(1))/( T_(1)) = (p_(2)V_(2))/( T_(2))`
`( p xx 4)/( T ) = ( 2p xx V_(2))/( 2T)`
`:. V_(2) = 4 dm^(3)`