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0.5 mol each of H(2), SO(2) and CH(4) ar...

0.5 mol each of `H_(2), SO_(2)` and `CH_(4)` are ketp in a container. A hole was made in the container. After 3 hours, the order of partial pressure in the container will be `:`

A

`pSO_(2) gt pCH_(4) gt pH_(2)`

B

`pH_(2) gt pSO_(2) gt pCH_(4)`

C

`pH_(2) gt pCH_(4) gtpSO_(2)`

D

`pSO_(2) gt pH_(2) gt pCH_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A

According to Graham.s law, the rate of effusion of a gas is inversely proportional to square root of its molar mass. Therefore, gases having less mass will effuse to a greater extent. Thus, the rate of effusion of the gases will be in the order `:`
`H_(2) gt CH_(4) gt SO_(2)`
`:.` the order of partial pressures in the container will be `: p SO_(2) gt pCH_(4) gt pH_(2)`
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