Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, The carbon marked with asterisk is most electronegative ?

Options

A. `CH_(3)-CH_(2)-""^(**)CH_(2)-CH_(3)`
B. `CH_(3)-""^(**)CH=CH-CH_(3)`
C. `CH_(3)-CH_(2)-C-=""^(**)CH`
D. `CH_(3)-CH_(2)-CH=""^(**)CH_(2)`

Answer

C

Explanation

Electronegativity increases as the state of hybridisation changes from `sp^(3)` to `sp^(2)` to sp. Therefore, sp-carbon has the highest electronegativity.