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The rate of the reaction 2SO(2) +O(2) ...

The rate of the reaction
`2SO_(2) +O_(2) rarr 2SO_(3)`
may be expressed as :
`-(d[O_(2)])/(dt)= 2.5 xx10^(-4) "mol L"^(-1) "sec"^(-1)`
The rate of reaction when expressed in terms of `SO_(3)` will be :

A

`-5.0xx10^(-4) "mol L"^(-1) "sec"^(-1)`

B

`-1.25xx10^(-4) "mol L"^(-1) "sec"^(-1)`

C

`3.75xx10^(-4) "mol L"^(-1) "sec"^(-1) `

D

`5.0xx10^(-4) "mol L"^(4) "sec"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
(D) Rate `= -(1)/(2) (d[SO_(2)])/(dt) =-(d[O_(2)])/(dt)`
`(d[SO_(2)])/(dt)=2 (d[O_(2)])/(dt)`
`=2xx2.5 xx10^(-4) `
`= 5.0 xx10^(-4)mol L^(-1) sec^(-I)`
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