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A reactant (A) forms two products : A ...

A reactant (A) forms two products :
`A overset(k_(1))(rarr)B ` Activation Energy `E_(a_(1))`
`A overset(k_(2))(rarr)C ` Activation Energy `E_(a_(2))`
If `E_(a_(1))` then `k_(1)` and `k_(2)` are related as :

A

`k_(2)=k_(1)e^(E_(a_(1))//RT)`

B

`k_(1)=k_(2)e^(E_(a_(1))//RT)`

C

`k_(1)=Ak_(2)e^(E_(a_(1))//RT)`

D

`k_(1)=2k_(2)e^(E_(a_(2))//RT)`

Text Solution

Verified by Experts

The correct Answer is:
C
( C) `k_(1) =A_(1)e^(-E_(a1)//RT)`
`k_(2) = A_(2)e^(-E_(a2)//RT)`
`(k_(2))/(k_(2))=((A_(1))/(A_(2))) e^((-E_(a1)+E_(a_(2)))/(RT)`
Now `(A_(1))/(A_(2))` = constant and `E_(a2)= 2E_(a1)`
`(k_(1))/(k_(2))=Ae^(E_(a1)//RT)`
`K_(1)= Ak_(2)e^(E_(a1)//RT)`
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