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For a first order reaction (A) rarr prod...

For a first order reaction `(A) rarr` products the concentration of A changes from 0.1 M to 0.025 M in 40 minutes . The rate of reaction when the concentration of A is 0.01 M is :

A

`1.73xx10^(-4) M//min`

B

`1.73xx10^(-5)` M/min

C

`3.47xx10^(-4)` M/min

D

`3.47 xx10^(-5)` M/min

Text Solution

Verified by Experts

The correct Answer is:
C
( C) `k= (2.303)/(t) "log" ([A]_(0))/([A])`
`k = (2.303)/(40) "log"(0.1)/(0.025) = 0.03466`
Rate =`k[A] = 0.03466xx0.01`
`=3.466xx10^(-4) M "min"^(-1)`
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