The position coordinate of a moving particle is given by `x=6+18t+9t^(2)` ('x' in 'm' and 't' is 's') what is its velocity at `t=2s`?

The position coordinate of a moving particle is given by x = 6 + 18t + 9t^(2) (x in metres and t in seconds). What is its velocity at l = 2 sec.

The position coordinate of a moving particle is given by x = 6+18t +9 t^(2) (where x is in metre, t in seconds. What is its velocity and acceleration at t = 2 s.

Completion type Question : The position coordinate of a moving particle is given by x = 6 + 18t + 9t^(2) (x is in metres and t in seconds) At t = 2s, the velocity of the particle will be …………

The velocity of a moving particle is given by v = 6 +18t + 9t^(2) (x in metre t in second ) what is its acceleration at t = 2 s?

The position of a moving particle is given by x = 6 + 18t + 9t^2 where x is the distance and t is the time. What is the velocity at t = 2sec.

The position-time relation of a moving particle is x = 2t -3t^(2) . What is the maximum positive velocity of the particle?

The position of a particle moving on a straight line path is given by X=12+18t+9t^2 metres.Find the instantaneous velocity at t=5s[dx/dt=v]

The position of a particle moving in a straight line is given by x=3t^(3)-18t^(2)+36t Here, x is in m and t in second. Then

The position of a particle moving in a string line is given by x = 3t^(3) - 18 t^(2) + 36 t Here, x is in m and t in second . Then

The displacement ( in meter ) of a particle moving along x-axis is given by x = 18t+ 5t^2 . Calculate instantaneous velocity at t = 2s