If an air bubbles rises from the bottom of a mercury tank to the top its volume becomes `1(1)/(2)` times. When normal pressure is `76 cm` of `Hg` then the depth of the `Hg` tank is

If an air bubble rises from the bottom of a mercury tank to the top its volume becomes 1(1/2) times. When normal pressure is 76 cm of Hg then the depth of the Hg tank is

When an air bubbles reaches the top of a lake from the bottom , its volume becomes 8 times . If the atmospheric pressure is 75 cms of Hg , the depth of lake is nearly

When an air bubble rises from the bottom of a lake to the upper surface , its diameter increases from 1mm to 2mm. IF the atmospheric pressure is 76 cmHg,calculate the depth of the lake. Density of mercury is 13.6g.cm^-3 .

As an air bubble rises from the bottom of a lake to the surface, its volume is doubled. Find the depth of the lake. Take atmospheric pressure = 76 cm of Hg.

As an air bubble rises from the bottom of a lake to the surface, its volume is doubled. Find the depth of the lake. Take atmospheric pressure = 76 cm of Hg.

As an air bubble rises from the bottom of a lake to the surface, its volume is doubled. Find the depth of the lake. Take atmospheric pressure = 76 cm of Hg.

When an air bubble rises from the bottom of a sea its volume increases to 4 times its initial value. IF the atmospheric pressure is 76 cmHg and the temperatures at the bottom and the surface of the sea are the same. Then what will be the depth of the sea? Density of mercury= 13.6 g.cm^-3 .