Statement I if `A,B,C,D` are angles of a cyclic quadrilateral then `sum sin A=0.`
Statement II If A, B, C, D are angles of cyclic quadrilateral then, `sum cos A=0.`

If A,B,C,D are the angles of a cyclic quadrilateral then sinA+sinB=

If A, B, C, D are angles of a cyclic quadrilateral then P.T sin A - sin C = sin D - sin B .

If A,B,C,D are the angles of a cyclic quadrilateral then cos A + cos B+ cos C + cos D=

I: If A,B,C,D are angles of a cyclic quadrilateral then cos A + cos B + cos C + cos D=0 II : If A,B,C,D are the angles of a quadrilateral then cos""(A+B)/(2) + cos""(C+D)/(2) =0

If A,B,C,D are angles of a cyclic quadrilateral,prove that cos A+cos B+cos C+cos D=0

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A,B,C,D are the angles of quadrilateral, then find (sum tan A)/(sum cot A).