If `int(dx)/(5-4cosx)=Atan^(-1)(Btanx//2)+C`, then

If int(dx)/(5+4cosx)=ktan^(-1)(mtan""(x)/(2))+c , then

If int(dx)/(5+4cosx)=ktan^(-1)(mtan""(x)/(2))+c , then

int dx/(4+5cosx) =

int(dx)/(5+4cosx)=atan^(-1)(b" tan"(x)/(2))+C , then a) a=(2)/(3),b=-1/3 b) a=2/3,b=1/3 c) a=-2/3,b=1/3 d) a=-2/3,b=-1/3

int dx/(5 + 4 cosx)

If int1/(5+4sinx)\ dx=Atan^(-1)(Btanx/2+4/3)+C , then A=2/3,\ \ B=5/3 (b) A=1/3,\ \ B=2/3 (c) A=-2/3,\ \ B=5/3 (d) A=1/3,\ \ B=-5/3

int(dx)/(5+4cosx)=lambdatan^(-1)(mtan.(x)/(2))+C then

int(dx)/(5+4cosx)=lambdatan^(-1)(mtan.(x)/(2))+C then

Evaluate int(dx)/(5+4cosx)= a tan^(-1) (b t a n (x/2))+C , then