The distance covered by a particle in `t` second is given by `x=3+8t-4t^(2)`. After `1s` its velocity will be

The distance covered by a particle in t seconds is given by x=3+8t-4t^(2) . After 1 second its velocity will be

The distance covered by a particle in t sec is given by x=3+8t-4t^(2) . What will be its velocity after 1 second.

If the distance s metre traversed by a particle in t seconds is given by s=t^(3)-3t^(2) , then the velocity of the particle when the acceleration is zero, in metre/second is

The distance 's' described by a particle in t seconds is given by s=ae^t+be^-t . The velocity at any time t is

The distance travelled s in metres by a particle in t second is given by s=t^(3)+2t^(2)+t . The speed of the particle after 1s will be

The distance s metres covered by a body in t seconds, is given by s = 3t^(2)-8t +5 , the body will stop after

The distance s feet travelled by a particle in time t seconds is given by s=t^3-6t^2-4t-8 . It's acceleration vanishes at time t =