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" (i) "int(0)^(1)sin^(-1)sqrt(x)dx=(pi)/...

" (i) "int_(0)^(1)sin^(-1)sqrt(x)dx=(pi)/(4)

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int_(0)^(1) sin^(-1) x dx =(pi)/(2) -1

int_(0)^(1) sin^(-1) x dx =(pi)/(2) -1

[-int_(0)^(1)sqrt(1-x)dx],[=(pi)/(2)-1]

int_(0)^( pi)sqrt(1+sin x)dx

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int_(0)^(2pi)sqrt(1+"sin"x/2)dx=

int_(0)^(2pi)sqrt(1+"sin"x/2)dx=