" If "y=a+bx^(2)," where "a,b" are constants,then "

If y=a+bx^(2) , where a, b are arbitrary constants, then

The equation of motion of a projectile is y = ax - bx^(2) , where a and b are constants of motion. Match the quantities in Column I with the relations in Column II.

The equation of motion of a projectile is y = ax - bx^(2) , where a and b are constants of motion. Match the quantities in Column I with the relations in Column II.

The path of a projectile is given by the equation y = ax – bx^(2) , where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively.

The trajectory of a projectile in a vertical plane is y=ax-bx^(2) , where a and b are constants and x and y are respectively horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection form the horizontal are:

The equation of motion of a projectile is y=ax-bx^(2) , where a and b are constants of motion. Match the quantities of column I with the relations of column II.

If y^(2) = ax^(2) + bx + c , where a,b,c, are constants , then y^(3) (d^(2) y)/(dx^(2)) is equal to