Light of wavelength `lambda` from a point source falls on a small circular rings around a central bright spot are formed on a screen beyond the obstacle The distance beetween the screen and obstacle is D. Then, the condition for the formation of rings, is

A beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and resulting diffraction pattern is observed on a screen 2m away. What is the distance between the first bright fringes on either side of the central bright fringe ?

A beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and resulting diffraction pattern is observed on a screen 2m away. What is the distance between the first bright fringes on either side of the central bright fringe ?

Fresnel diffraction is produced due to light rays falling on a small obstacle. The intensity of light at a point on a screen beyond an obstacle depends on

A light of wavelength lambda falls on a narrow slit of width d.A diffraction fringe is formed on a screen placed at distance D from the slit. If the linear width of the central maximum equals to the width of the slit, will be the value of D?

Light from a point source falls on a screen. If the separation between the source and the screen is increased by 1%, the illuminance will decrease (nearly) by

Light from a point source falls on a screen. If the separation between the source and the screen is increased by 1%, the illuminance will decrease (nearly) by

Light from a point source falls on a screen. If the separation between the source and the screen is increased by 1%, the illuminance will decrease (nearly) by

Light of wavelength 500 nm is incident on a slit of width 0.1 mm. The width of the central bright line on the screen is 2 mm. The distance of the screen is

In Fraunhofer diffraction experiment, L is the distance between screen and the obstacle, b is the size of obstacle and lambda is wavelength of incident light. The general condition for the applicability of Fraunhofer diffraction is :